Solve 25/6*(-3)/2+(-1frac{3{4})}=

$$\frac { 2 \frac { 5 } { 6 } \cdot ( - 3 ) } { 2 + ( - 1 \frac { 3 } { 4 } ) } =$$

Evaluate

$$-34$$

Solution Steps

Multiply 2 and 6 to get 12.

$$\frac{\frac{12+5}{6}\left(-3\right)}{2-\frac{1\times 4+3}{4}}$$

Add 12 and 5 to get 17.

$$\frac{\frac{17}{6}\left(-3\right)}{2-\frac{1\times 4+3}{4}}$$

Express \frac{17}{6}\left(-3\right) as a single fraction.

$$\frac{\frac{17\left(-3\right)}{6}}{2-\frac{1\times 4+3}{4}}$$

Multiply 17 and -3 to get -51.

$$\frac{\frac{-51}{6}}{2-\frac{1\times 4+3}{4}}$$

Reduce the fraction \frac{-51}{6} to lowest terms by extracting and canceling out 3.

$$\frac{-\frac{17}{2}}{2-\frac{1\times 4+3}{4}}$$

Multiply 1 and 4 to get 4.

$$\frac{-\frac{17}{2}}{2-\frac{4+3}{4}}$$

Add 4 and 3 to get 7.

$$\frac{-\frac{17}{2}}{2-\frac{7}{4}}$$

Convert 2 to fraction \frac{8}{4}.

$$\frac{-\frac{17}{2}}{\frac{8}{4}-\frac{7}{4}}$$

Since \frac{8}{4} and \frac{7}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-\frac{17}{2}}{\frac{8-7}{4}}$$

Subtract 7 from 8 to get 1.

$$\frac{-\frac{17}{2}}{\frac{1}{4}}$$

Divide -\frac{17}{2} by \frac{1}{4} by multiplying -\frac{17}{2} by the reciprocal of \frac{1}{4}.

$$-\frac{17}{2}\times 4$$

Express -\frac{17}{2}\times 4 as a single fraction.

$$\frac{-17\times 4}{2}$$

Multiply -17 and 4 to get -68.

$$\frac{-68}{2}$$

Divide -68 by 2 to get -34.

$$-34$$

Factor

$$-34$$