Solve 2*5-3*(4-5)+1/3-(7+3)=

$$\frac { 2 \cdot 5 - 3 \cdot ( 4 - 5 ) + 1 } { 3 - ( 7 + 3 ) } =$$

Evaluate

$$-2$$

Solution Steps

Multiply 2 and 5 to get 10.

$$\frac{10-3\left(4-5\right)+1}{3-\left(7+3\right)}$$

Subtract 5 from 4 to get -1.

$$\frac{10-3\left(-1\right)+1}{3-\left(7+3\right)}$$

Multiply 3 and -1 to get -3.

$$\frac{10-\left(-3\right)+1}{3-\left(7+3\right)}$$

The opposite of -3 is 3.

$$\frac{10+3+1}{3-\left(7+3\right)}$$

Add 10 and 3 to get 13.

$$\frac{13+1}{3-\left(7+3\right)}$$

Add 13 and 1 to get 14.

$$\frac{14}{3-\left(7+3\right)}$$

Add 7 and 3 to get 10.

$$\frac{14}{3-10}$$

Subtract 10 from 3 to get -7.

$$\frac{14}{-7}$$

Divide 14 by -7 to get -2.

$$-2$$

Factor

$$-2$$