Solve 2^3/2-5*2^2/2+6*2=

$$\frac { 2 ^ { 3 } } { 2 } - \frac { 5 \cdot 2 ^ { 2 } } { 2 } + 6 \cdot 2 =$$

Evaluate

$$6$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 1 from 3 to get 2.

$$2^{2}-\frac{5\times 2^{2}}{2}+6\times 2$$

Calculate 2 to the power of 2 and get 4.

$$4-\frac{5\times 2^{2}}{2}+6\times 2$$

Calculate 2 to the power of 2 and get 4.

$$4-\frac{5\times 4}{2}+6\times 2$$

Multiply 5 and 4 to get 20.

$$4-\frac{20}{2}+6\times 2$$

Divide 20 by 2 to get 10.

$$4-10+6\times 2$$

Subtract 10 from 4 to get -6.

$$-6+6\times 2$$

Multiply 6 and 2 to get 12.

$$-6+12$$

Add -6 and 12 to get 6.

$$6$$

Factor

$$2\times 3$$