Solve frac{2^3+3*8+sqrt[6]{3}}{8^2+3*5^7}

$$\frac { 2 ^ { 3 } + 3 \times 8 + \sqrt[ 6 ] { 3 } } { 8 ^ { 2 } + 3 \times 5 ^ { 7 } }$$

Evaluate

$$\frac{\sqrt[6]{3}+32}{234439}\approx 0.000141619$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$\frac{8+3\times 8+\sqrt[6]{3}}{8^{2}+3\times 5^{7}}$$

Multiply 3 and 8 to get 24.

$$\frac{8+24+\sqrt[6]{3}}{8^{2}+3\times 5^{7}}$$

Add 8 and 24 to get 32.

$$\frac{32+\sqrt[6]{3}}{8^{2}+3\times 5^{7}}$$

Calculate 8 to the power of 2 and get 64.

$$\frac{32+\sqrt[6]{3}}{64+3\times 5^{7}}$$

Calculate 5 to the power of 7 and get 78125.

$$\frac{32+\sqrt[6]{3}}{64+3\times 78125}$$

Multiply 3 and 78125 to get 234375.

$$\frac{32+\sqrt[6]{3}}{64+234375}$$

Add 64 and 234375 to get 234439.

$$\frac{32+\sqrt[6]{3}}{234439}$$