Solve 2^2/2-8+8/6

$$\frac { 2 ^ { 2 } } { 2 } - 8 + \frac { 8 } { 6 }$$

Evaluate

$$-\frac{14}{3}\approx -4.666666667$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 1 from 2 to get 1.

$$2^{1}-8+\frac{8}{6}$$

Calculate 2 to the power of 1 and get 2.

$$2-8+\frac{8}{6}$$

Subtract 8 from 2 to get -6.

$$-6+\frac{8}{6}$$

Reduce the fraction \frac{8}{6} to lowest terms by extracting and canceling out 2.

$$-6+\frac{4}{3}$$

Convert -6 to fraction -\frac{18}{3}.

$$-\frac{18}{3}+\frac{4}{3}$$

Since -\frac{18}{3} and \frac{4}{3} have the same denominator, add them by adding their numerators.

$$\frac{-18+4}{3}$$

Add -18 and 4 to get -14.

$$-\frac{14}{3}$$

Factor

$$-\frac{14}{3} = -4\frac{2}{3} = -4.666666666666667$$