Solve 2^0-(-2)^2/2^2+(-2)^3

$$\frac { 2 ^ { 0 } - ( - 2 ) ^ { 2 } } { 2 ^ { 2 } + ( - 2 ) ^ { 3 } }$$

Evaluate

$$\frac{3}{4}=0.75$$

Solution Steps

Calculate 2 to the power of 0 and get 1.

$$\frac{1-\left(-2\right)^{2}}{2^{2}+\left(-2\right)^{3}}$$

Calculate -2 to the power of 2 and get 4.

$$\frac{1-4}{2^{2}+\left(-2\right)^{3}}$$

Subtract 4 from 1 to get -3.

$$\frac{-3}{2^{2}+\left(-2\right)^{3}}$$

Calculate 2 to the power of 2 and get 4.

$$\frac{-3}{4+\left(-2\right)^{3}}$$

Calculate -2 to the power of 3 and get -8.

$$\frac{-3}{4-8}$$

Subtract 8 from 4 to get -4.

$$\frac{-3}{-4}$$

Fraction \frac{-3}{-4} can be simplified to \frac{3}{4} by removing the negative sign from both the numerator and the denominator.

$$\frac{3}{4}$$

Factor

$$\frac{3}{2 ^ {2}} = 0.75$$