Solve 2^-3*5^2/10^-1

$$\frac { 2 ^ { - 3 } \cdot 5 ^ { 2 } } { 10 ^ { - 1 } }$$

Evaluate

$$\frac{125}{4}=31.25$$

Solution Steps

Calculate 2 to the power of -3 and get \frac{1}{8}.

$$\frac{\frac{1}{8}\times 5^{2}}{10^{-1}}$$

Calculate 5 to the power of 2 and get 25.

$$\frac{\frac{1}{8}\times 25}{10^{-1}}$$

Multiply \frac{1}{8} and 25 to get \frac{25}{8}.

$$\frac{\frac{25}{8}}{10^{-1}}$$

Calculate 10 to the power of -1 and get \frac{1}{10}.

$$\frac{\frac{25}{8}}{\frac{1}{10}}$$

Divide \frac{25}{8} by \frac{1}{10} by multiplying \frac{25}{8} by the reciprocal of \frac{1}{10}.

$$\frac{25}{8}\times 10$$

Multiply \frac{25}{8} and 10 to get \frac{125}{4}.

$$\frac{125}{4}$$

Factor

$$\frac{5 ^ {3}}{2 ^ {2}} = 31\frac{1}{4} = 31.25$$