Solve 2+x/4+x/3-1-x/6=x/12+1

$$\frac { 2 + x } { 4 } + \frac { x } { 3 } - \frac { 1 - x } { 6 } = \frac { x } { 12 } + 1$$

Solve for x

$$x=1$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 12, the least common multiple of 4,3,6,12.

$$3\left(2+x\right)+4x-2\left(1-x\right)=x+12$$

Use the distributive property to multiply 3 by 2+x.

$$6+3x+4x-2\left(1-x\right)=x+12$$

Combine 3x and 4x to get 7x.

$$6+7x-2\left(1-x\right)=x+12$$

Use the distributive property to multiply -2 by 1-x.

$$6+7x-2+2x=x+12$$

Subtract 2 from 6 to get 4.

$$4+7x+2x=x+12$$

Combine 7x and 2x to get 9x.

$$4+9x=x+12$$

Subtract x from both sides.

$$4+9x-x=12$$

Combine 9x and -x to get 8x.

$$4+8x=12$$

Subtract 4 from both sides.

$$8x=12-4$$

Subtract 4 from 12 to get 8.

$$8x=8$$

Divide both sides by 8.

$$x=\frac{8}{8}$$

Divide 8 by 8 to get 1.

$$x=1$$