Solve 2+b/a=-2^x

$$\frac { 2 + b } { a } = - 2 ^ { x }$$

Solve for a

$$a=-\frac{b+2}{2^{x}}$$

$$b\neq -2$$

Steps for Solving Linear Equation

Variable a cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by a.

$$2+b=-a\times 2^{x}$$

Swap sides so that all variable terms are on the left hand side.

$$-a\times 2^{x}=2+b$$

Reorder the terms.

$$-a\times 2^{x}=b+2$$

The equation is in standard form.

$$\left(-2^{x}\right)a=b+2$$

Divide both sides by -2^{x}.

$$\frac{\left(-2^{x}\right)a}{-2^{x}}=\frac{b+2}{-2^{x}}$$

Dividing by -2^{x} undoes the multiplication by -2^{x}.

$$a=\frac{b+2}{-2^{x}}$$

Divide 2+b by -2^{x}.

$$a=-\frac{b+2}{2^{x}}$$

Variable a cannot be equal to 0.

$$a=-\frac{b+2}{2^{x}}\text{, }a\neq 0$$

Solve for b

$$b=-\left(a\times 2^{x}+2\right)$$

$$a\neq 0$$