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\frac{\left(2+3i\right)\left(5+7i\right)}{\left(5-7i\right)\left(5+7i\right)}
Multiply both numerator and denominator by the complex conjugate of the denominator, 5+7i.
\frac{\left(2+3i\right)\left(5+7i\right)}{5^{2}-7^{2}i^{2}}
Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\left(2+3i\right)\left(5+7i\right)}{74}
By definition, i^{2} is -1. Calculate the denominator.
\frac{2\times 5+2\times \left(7i\right)+3i\times 5+3\times 7i^{2}}{74}
Multiply complex numbers 2+3i and 5+7i like you multiply binomials.
\frac{2\times 5+2\times \left(7i\right)+3i\times 5+3\times 7\left(-1\right)}{74}
By definition, i^{2} is -1.
\frac{10+14i+15i-21}{74}
Do the multiplications in 2\times 5+2\times \left(7i\right)+3i\times 5+3\times 7\left(-1\right).
\frac{10-21+\left(14+15\right)i}{74}
Combine the real and imaginary parts in 10+14i+15i-21.
\frac{-11+29i}{74}
Do the additions in 10-21+\left(14+15\right)i.
-\frac{11}{74}+\frac{29}{74}i
Divide -11+29i by 74 to get -\frac{11}{74}+\frac{29}{74}i.
Re(\frac{\left(2+3i\right)\left(5+7i\right)}{\left(5-7i\right)\left(5+7i\right)})
Multiply both numerator and denominator of \frac{2+3i}{5-7i} by the complex conjugate of the denominator, 5+7i.
Re(\frac{\left(2+3i\right)\left(5+7i\right)}{5^{2}-7^{2}i^{2}})
Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
Re(\frac{\left(2+3i\right)\left(5+7i\right)}{74})
By definition, i^{2} is -1. Calculate the denominator.
Re(\frac{2\times 5+2\times \left(7i\right)+3i\times 5+3\times 7i^{2}}{74})
Multiply complex numbers 2+3i and 5+7i like you multiply binomials.
Re(\frac{2\times 5+2\times \left(7i\right)+3i\times 5+3\times 7\left(-1\right)}{74})
By definition, i^{2} is -1.
Re(\frac{10+14i+15i-21}{74})
Do the multiplications in 2\times 5+2\times \left(7i\right)+3i\times 5+3\times 7\left(-1\right).
Re(\frac{10-21+\left(14+15\right)i}{74})
Combine the real and imaginary parts in 10+14i+15i-21.
Re(\frac{-11+29i}{74})
Do the additions in 10-21+\left(14+15\right)i.
Re(-\frac{11}{74}+\frac{29}{74}i)
Divide -11+29i by 74 to get -\frac{11}{74}+\frac{29}{74}i.
-\frac{11}{74}
The real part of -\frac{11}{74}+\frac{29}{74}i is -\frac{11}{74}.