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\frac{\left(2+\frac{1}{3}\right)\times 5}{2-\frac{1}{3}}+\left(\frac{1}{3}\right)^{-1}
Divide \frac{2+\frac{1}{3}}{2-\frac{1}{3}} by \frac{1}{5} by multiplying \frac{2+\frac{1}{3}}{2-\frac{1}{3}} by the reciprocal of \frac{1}{5}.
\frac{\frac{7}{3}\times 5}{2-\frac{1}{3}}+\left(\frac{1}{3}\right)^{-1}
Add 2 and \frac{1}{3} to get \frac{7}{3}.
\frac{\frac{35}{3}}{2-\frac{1}{3}}+\left(\frac{1}{3}\right)^{-1}
Multiply \frac{7}{3} and 5 to get \frac{35}{3}.
\frac{\frac{35}{3}}{\frac{5}{3}}+\left(\frac{1}{3}\right)^{-1}
Subtract \frac{1}{3} from 2 to get \frac{5}{3}.
\frac{35}{3}\times \frac{3}{5}+\left(\frac{1}{3}\right)^{-1}
Divide \frac{35}{3} by \frac{5}{3} by multiplying \frac{35}{3} by the reciprocal of \frac{5}{3}.
7+\left(\frac{1}{3}\right)^{-1}
Multiply \frac{35}{3} and \frac{3}{5} to get 7.
7+3
Calculate \frac{1}{3} to the power of -1 and get 3.
10
Add 7 and 3 to get 10.