Solve 19*1/3/3+7/3=

$$\frac { 19 \times \frac { 1 } { 3 } } { 3 } + \frac { 7 } { 3 } =$$

Evaluate

$$\frac{40}{9}\approx 4.444444444$$

Solution Steps

Multiply 19 and \frac{1}{3} to get \frac{19}{3}.

$$\frac{\frac{19}{3}}{3}+\frac{7}{3}$$

Express \frac{\frac{19}{3}}{3} as a single fraction.

$$\frac{19}{3\times 3}+\frac{7}{3}$$

Multiply 3 and 3 to get 9.

$$\frac{19}{9}+\frac{7}{3}$$

Least common multiple of 9 and 3 is 9. Convert \frac{19}{9} and \frac{7}{3} to fractions with denominator 9.

$$\frac{19}{9}+\frac{21}{9}$$

Since \frac{19}{9} and \frac{21}{9} have the same denominator, add them by adding their numerators.

$$\frac{19+21}{9}$$

Add 19 and 21 to get 40.

$$\frac{40}{9}$$

Factor

$$\frac{2 ^ {3} \cdot 5}{3 ^ {2}} = 4\frac{4}{9} = 4.444444444444445$$