Solve 18z^4/2z^8div81z/6z^8

$$\frac { 18 z ^ { 4 } } { 2 z ^ { 8 } } \div \frac { 81 z } { 6 z ^ { 8 } }$$

Evaluate

$$\frac{2z^{3}}{3}$$

Solution Steps

Divide \frac{18z^{4}}{2z^{8}} by \frac{81z}{6z^{8}} by multiplying \frac{18z^{4}}{2z^{8}} by the reciprocal of \frac{81z}{6z^{8}}.

$$\frac{18z^{4}\times 6z^{8}}{2z^{8}\times 81z}$$

Cancel out 2\times 3\times 9zz^{4}z^{4} in both numerator and denominator.

$$\frac{2z^{3}}{3}$$

Differentiate w.r.t. z

$$2z^{2}$$