Solve 18x^7/y^3div3x^7y^3/7

$$\frac { 18 x ^ { 7 } } { y ^ { 3 } } \div \frac { 3 x ^ { 7 } y ^ { 3 } } { 7 }$$

Evaluate

$$\frac{42}{y^{6}}$$

Solution Steps

Divide \frac{18x^{7}}{y^{3}} by \frac{3x^{7}y^{3}}{7} by multiplying \frac{18x^{7}}{y^{3}} by the reciprocal of \frac{3x^{7}y^{3}}{7}.

$$\frac{18x^{7}\times 7}{y^{3}\times 3x^{7}y^{3}}$$

Cancel out 3x^{7} in both numerator and denominator.

$$\frac{6\times 7}{y^{3}y^{3}}$$

Multiply 6 and 7 to get 42.

$$\frac{42}{y^{3}y^{3}}$$

To multiply powers of the same base, add their exponents. Add 3 and 3 to get 6.

$$\frac{42}{y^{6}}$$

Differentiate w.r.t. y

$$-\frac{252}{y^{7}}$$