Solve 18x^3y/14x^3y^4

$$\frac { 18 x ^ { 3 } y } { 14 x ^ { 3 } y ^ { 4 } }$$

Evaluate

$$\frac{9}{7y^{3}}$$

Steps Using Quotient of Powers Property

Use the rules of exponents to simplify the expression.

$$\frac{18^{1}x^{3}y^{1}}{14^{1}x^{3}y^{4}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$\frac{18^{1}}{14^{1}}x^{3-3}y^{1-4}$$

Subtract 3 from 3.

$$\frac{18^{1}}{14^{1}}x^{0}y^{1-4}$$

For any number a except 0, a^{0}=1.

$$\frac{18^{1}}{14^{1}}y^{1-4}$$

Subtract 4 from 1.

$$\frac{18^{1}}{14^{1}}y^{-3}$$

Reduce the fraction \frac{18}{14} to lowest terms by extracting and canceling out 2.

$$\frac{9}{7}\times \frac{1}{y^{3}}$$

Differentiate w.r.t. y

$$-\frac{27}{7y^{4}}$$