Solve 18c^3/-3c^2quad13)

$$\frac { 18 c ^ { 3 } } { - 3 c ^ { 2 } } \quad 13 )$$

Evaluate

$$-78c$$

Solution Steps

Cancel out 3c^{2} in both numerator and denominator.

$$\frac{6c}{-1}\times 13$$

Anything divided by -1 gives its opposite.

$$-6c\times 13$$

Multiply -6 and 13 to get -78.

$$-78c$$

Differentiate w.r.t. c

$$-78$$

Steps Using Definition of a Derivative

Cancel out 3c^{2} in both numerator and denominator.

$$\frac{\mathrm{d}}{\mathrm{d}c}(\frac{6c}{-1}\times 13)$$

Anything divided by -1 gives its opposite.

$$\frac{\mathrm{d}}{\mathrm{d}c}(-6c\times 13)$$

Multiply -6 and 13 to get -78.

$$\frac{\mathrm{d}}{\mathrm{d}c}(-78c)$$

The derivative of ax^{n} is nax^{n-1}.

$$-78c^{1-1}$$

Subtract 1 from 1.

$$-78c^{0}$$

For any term t except 0, t^{0}=1.

$$-78$$