Solve 18b/200+03

$$\frac { 18 b } { 200 } + 03$$

Evaluate

$$\frac{9b}{100}$$

Solution Steps

Divide 18b by 200 to get \frac{9}{100}b.

$$\frac{9}{100}b+0\times 3$$

Multiply 0 and 3 to get 0.

$$\frac{9}{100}b+0$$

Anything plus zero gives itself.

$$\frac{9}{100}b$$

Differentiate w.r.t. b

$$\frac{9}{100} = 0.09$$

Steps Using Definition of a Derivative

Divide 18b by 200 to get \frac{9}{100}b.

$$\frac{\mathrm{d}}{\mathrm{d}b}(\frac{9}{100}b+0\times 3)$$

Multiply 0 and 3 to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}b}(\frac{9}{100}b+0)$$

Anything plus zero gives itself.

$$\frac{\mathrm{d}}{\mathrm{d}b}(\frac{9}{100}b)$$

The derivative of ax^{n} is nax^{n-1}.

$$\frac{9}{100}b^{1-1}$$

Subtract 1 from 1.

$$\frac{9}{100}b^{0}$$

For any term t except 0, t^{0}=1.

$$\frac{9}{100}\times 1$$

For any term t, t\times 1=t and 1t=t.

$$\frac{9}{100}$$