Solve 18-3(6-8)/6[8-4(5-2]-1=

$$\frac { 18 - 3 ( 6 - 8 ) } { 6 [ 8 - 4 ( 5 - 2 ] - 1 } =$$

Evaluate

$$-\frac{4}{5}=-0.8$$

Solution Steps

Subtract 8 from 6 to get -2.

$$\frac{18-3\left(-2\right)}{6\left(8-4\left(5-2\right)-1\right)}$$

Multiply 3 and -2 to get -6.

$$\frac{18-\left(-6\right)}{6\left(8-4\left(5-2\right)-1\right)}$$

The opposite of -6 is 6.

$$\frac{18+6}{6\left(8-4\left(5-2\right)-1\right)}$$

Add 18 and 6 to get 24.

$$\frac{24}{6\left(8-4\left(5-2\right)-1\right)}$$

Subtract 2 from 5 to get 3.

$$\frac{24}{6\left(8-4\times 3-1\right)}$$

Multiply 4 and 3 to get 12.

$$\frac{24}{6\left(8-12-1\right)}$$

Subtract 12 from 8 to get -4.

$$\frac{24}{6\left(-4-1\right)}$$

Subtract 1 from -4 to get -5.

$$\frac{24}{6\left(-5\right)}$$

Multiply 6 and -5 to get -30.

$$\frac{24}{-30}$$

Reduce the fraction \frac{24}{-30} to lowest terms by extracting and canceling out 6.

$$-\frac{4}{5}$$

Factor

$$-\frac{4}{5} = -0.8$$