Solve 18/10*42/45*25/27=

$$\frac { 18 } { 10 } \cdot \frac { 42 } { 45 } \cdot \frac { 25 } { 27 } =$$

Evaluate

$$\frac{14}{9}\approx 1.555555556$$

Solution Steps

Reduce the fraction \frac{18}{10} to lowest terms by extracting and canceling out 2.

$$\frac{9}{5}\times \frac{42}{45}\times \frac{25}{27}$$

Reduce the fraction \frac{42}{45} to lowest terms by extracting and canceling out 3.

$$\frac{9}{5}\times \frac{14}{15}\times \frac{25}{27}$$

Multiply \frac{9}{5} times \frac{14}{15} by multiplying numerator times numerator and denominator times denominator.

$$\frac{9\times 14}{5\times 15}\times \frac{25}{27}$$

Do the multiplications in the fraction \frac{9\times 14}{5\times 15}.

$$\frac{126}{75}\times \frac{25}{27}$$

Reduce the fraction \frac{126}{75} to lowest terms by extracting and canceling out 3.

$$\frac{42}{25}\times \frac{25}{27}$$

Multiply \frac{42}{25} times \frac{25}{27} by multiplying numerator times numerator and denominator times denominator.

$$\frac{42\times 25}{25\times 27}$$

Cancel out 25 in both numerator and denominator.

$$\frac{42}{27}$$

Reduce the fraction \frac{42}{27} to lowest terms by extracting and canceling out 3.

$$\frac{14}{9}$$

Factor

$$\frac{2 \cdot 7}{3 ^ {2}} = 1\frac{5}{9} = 1.5555555555555556$$