Solve 17/3>5y+4/6

$$\frac { 17 } { 3 } > \frac { 5 y + 4 } { 6 }$$

Solve for y

$$y<6$$

Solution Steps

Multiply both sides by 6. Since 6 is positive, the inequality direction remains the same.

$$\frac{17}{3}\times 6>5y+4$$

Express \frac{17}{3}\times 6 as a single fraction.

$$\frac{17\times 6}{3}>5y+4$$

Multiply 17 and 6 to get 102.

$$\frac{102}{3}>5y+4$$

Divide 102 by 3 to get 34.

$$34>5y+4$$

Swap sides so that all variable terms are on the left hand side. This changes the sign direction.

$$5y+4<34$$

Subtract 4 from both sides.

$$5y<34-4$$

Subtract 4 from 34 to get 30.

$$5y<30$$

Divide both sides by 5. Since 5 is positive, the inequality direction remains the same.

$$y<\frac{30}{5}$$

Divide 30 by 5 to get 6.

$$y<6$$