Solve 16a^2-24a+9/a^2-64*a+8/-4a+3

$$\frac { 16 a ^ { 2 } - 24 a + 9 } { a ^ { 2 } - 64 } \times \frac { a + 8 } { - 4 a + 3 }$$

Evaluate

$$-\frac{4a-3}{a-8}$$

Short Solution Steps

Multiply \frac{16a^{2}-24a+9}{a^{2}-64} times \frac{a+8}{-4a+3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\left(16a^{2}-24a+9\right)\left(a+8\right)}{\left(a^{2}-64\right)\left(-4a+3\right)}$$

Factor the expressions that are not already factored.

$$\frac{\left(a+8\right)\left(4a-3\right)^{2}}{\left(a-8\right)\left(a+8\right)\left(-4a+3\right)}$$

Cancel out a+8 in both numerator and denominator.

$$\frac{\left(4a-3\right)^{2}}{\left(a-8\right)\left(-4a+3\right)}$$

Expand the expression.

$$\frac{16a^{2}-24a+9}{-4a^{2}+35a-24}$$

Factor the expressions that are not already factored.

$$\frac{\left(4a-3\right)^{2}}{\left(4a-3\right)\left(-a+8\right)}$$

Cancel out 4a-3 in both numerator and denominator.

$$\frac{4a-3}{-a+8}$$

Expand

$$-\frac{4a-3}{a-8}$$

Short Solution Steps

Multiply \frac{16a^{2}-24a+9}{a^{2}-64} times \frac{a+8}{-4a+3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\left(16a^{2}-24a+9\right)\left(a+8\right)}{\left(a^{2}-64\right)\left(-4a+3\right)}$$

Factor the expressions that are not already factored.

$$\frac{\left(a+8\right)\left(4a-3\right)^{2}}{\left(a-8\right)\left(a+8\right)\left(-4a+3\right)}$$

Cancel out a+8 in both numerator and denominator.

$$\frac{\left(4a-3\right)^{2}}{\left(a-8\right)\left(-4a+3\right)}$$

Expand the expression.

$$\frac{16a^{2}-24a+9}{-4a^{2}+35a-24}$$

Factor the expressions that are not already factored.

$$\frac{\left(4a-3\right)^{2}}{\left(4a-3\right)\left(-a+8\right)}$$

Cancel out 4a-3 in both numerator and denominator.

$$\frac{4a-3}{-a+8}$$