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\frac{64a^{2}-9b^{2}}{36}
Factor out \frac{1}{36}.
\left(8a-3b\right)\left(8a+3b\right)
Consider 64a^{2}-9b^{2}. Rewrite 64a^{2}-9b^{2} as \left(8a\right)^{2}-\left(3b\right)^{2}. The difference of squares can be factored using the rule: p^{2}-q^{2}=\left(p-q\right)\left(p+q\right).
\frac{\left(8a-3b\right)\left(8a+3b\right)}{36}
Rewrite the complete factored expression.