Solve 16/61*3/4-5/4:3/4=

$$\frac { 16 } { 61 } \times \frac { 3 } { 4 } - \frac { 5 } { 4 } : \frac { 3 } { 4 } =$$

Evaluate

$$-\frac{269}{183}\approx -1.469945355$$

Solution Steps

Multiply \frac{16}{61} times \frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{16\times 3}{61\times 4}-\frac{\frac{5}{4}}{\frac{3}{4}}$$

Do the multiplications in the fraction \frac{16\times 3}{61\times 4}.

$$\frac{48}{244}-\frac{\frac{5}{4}}{\frac{3}{4}}$$

Reduce the fraction \frac{48}{244} to lowest terms by extracting and canceling out 4.

$$\frac{12}{61}-\frac{\frac{5}{4}}{\frac{3}{4}}$$

Divide \frac{5}{4} by \frac{3}{4} by multiplying \frac{5}{4} by the reciprocal of \frac{3}{4}.

$$\frac{12}{61}-\frac{5}{4}\times \frac{4}{3}$$

Multiply \frac{5}{4} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{12}{61}-\frac{5\times 4}{4\times 3}$$

Cancel out 4 in both numerator and denominator.

$$\frac{12}{61}-\frac{5}{3}$$

Least common multiple of 61 and 3 is 183. Convert \frac{12}{61} and \frac{5}{3} to fractions with denominator 183.

$$\frac{36}{183}-\frac{305}{183}$$

Since \frac{36}{183} and \frac{305}{183} have the same denominator, subtract them by subtracting their numerators.

$$\frac{36-305}{183}$$

Subtract 305 from 36 to get -269.

$$-\frac{269}{183}$$

Factor

$$-\frac{269}{183} = -1\frac{86}{183} = -1.469945355191257$$