Solve 16/45div11/9=

$$\frac { 16 } { 45 } \div 1 \frac { 1 } { 9 } =$$

Evaluate

$$\frac{8}{25}=0.32$$

Solution Steps

Divide \frac{16}{45} by \frac{1\times 9+1}{9} by multiplying \frac{16}{45} by the reciprocal of \frac{1\times 9+1}{9}.

$$\frac{16\times 9}{45\left(1\times 9+1\right)}$$

Cancel out 9 in both numerator and denominator.

$$\frac{16}{5\left(1+9\right)}$$

Add 1 and 9 to get 10.

$$\frac{16}{5\times 10}$$

Multiply 5 and 10 to get 50.

$$\frac{16}{50}$$

Reduce the fraction \frac{16}{50} to lowest terms by extracting and canceling out 2.

$$\frac{8}{25}$$

Factor

$$\frac{2 ^ {3}}{5 ^ {2}} = 0.32$$