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11x-\frac{2}{7}=-\frac{30}{7}+\frac{16}{3}x+\frac{7}{3}x
Combine \frac{16}{3}x and \frac{17}{3}x to get 11x.
11x-\frac{2}{7}=-\frac{30}{7}+\frac{23}{3}x
Combine \frac{16}{3}x and \frac{7}{3}x to get \frac{23}{3}x.
11x-\frac{2}{7}-\frac{23}{3}x=-\frac{30}{7}
Subtract \frac{23}{3}x from both sides.
\frac{10}{3}x-\frac{2}{7}=-\frac{30}{7}
Combine 11x and -\frac{23}{3}x to get \frac{10}{3}x.
\frac{10}{3}x=-\frac{30}{7}+\frac{2}{7}
Add \frac{2}{7} to both sides.
\frac{10}{3}x=\frac{-30+2}{7}
Since -\frac{30}{7} and \frac{2}{7} have the same denominator, add them by adding their numerators.
\frac{10}{3}x=\frac{-28}{7}
Add -30 and 2 to get -28.
\frac{10}{3}x=-4
Divide -28 by 7 to get -4.
x=-4\times \frac{3}{10}
Multiply both sides by \frac{3}{10}, the reciprocal of \frac{10}{3}.
x=\frac{-4\times 3}{10}
Express -4\times \frac{3}{10} as a single fraction.
x=\frac{-12}{10}
Multiply -4 and 3 to get -12.
x=-\frac{6}{5}
Reduce the fraction \frac{-12}{10} to lowest terms by extracting and canceling out 2.