Solve 16/2-28/8+7/3=

$$\frac { 16 } { 2 } - \frac { 28 } { 8 } + \frac { 7 } { 3 } =$$

Evaluate

$$\frac{41}{6}\approx 6.833333333$$

Solution Steps

Divide 16 by 2 to get 8.

$$8-\frac{28}{8}+\frac{7}{3}$$

Reduce the fraction \frac{28}{8} to lowest terms by extracting and canceling out 4.

$$8-\frac{7}{2}+\frac{7}{3}$$

Convert 8 to fraction \frac{16}{2}.

$$\frac{16}{2}-\frac{7}{2}+\frac{7}{3}$$

Since \frac{16}{2} and \frac{7}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{16-7}{2}+\frac{7}{3}$$

Subtract 7 from 16 to get 9.

$$\frac{9}{2}+\frac{7}{3}$$

Least common multiple of 2 and 3 is 6. Convert \frac{9}{2} and \frac{7}{3} to fractions with denominator 6.

$$\frac{27}{6}+\frac{14}{6}$$

Since \frac{27}{6} and \frac{14}{6} have the same denominator, add them by adding their numerators.

$$\frac{27+14}{6}$$

Add 27 and 14 to get 41.

$$\frac{41}{6}$$

Factor

$$\frac{41}{2 \cdot 3} = 6\frac{5}{6} = 6.833333333333333$$