Solve 16*6/12*36+5x/15*27=1

$$\frac { 16 \times 6 } { 12 \times 36 } + \frac { 5 x } { 15 \times 27 } = 1$$

Solve for x

$$x=63$$

Steps for Solving Linear Equation

Cancel out 3\times 4\times 4 in both numerator and denominator.

$$\frac{2}{9}+\frac{5x}{15\times 27}=1$$

Cancel out 5 in both numerator and denominator.

$$\frac{2}{9}+\frac{x}{3\times 27}=1$$

Multiply 3 and 27 to get 81.

$$\frac{2}{9}+\frac{x}{81}=1$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 9 and 81 is 81. Multiply \frac{2}{9} times \frac{9}{9}.

$$\frac{2\times 9}{81}+\frac{x}{81}=1$$

Since \frac{2\times 9}{81} and \frac{x}{81} have the same denominator, add them by adding their numerators.

$$\frac{2\times 9+x}{81}=1$$

Do the multiplications in 2\times 9+x.

$$\frac{18+x}{81}=1$$

Divide each term of 18+x by 81 to get \frac{2}{9}+\frac{1}{81}x.

$$\frac{2}{9}+\frac{1}{81}x=1$$

Subtract \frac{2}{9} from both sides.

$$\frac{1}{81}x=1-\frac{2}{9}$$

Convert 1 to fraction \frac{9}{9}.

$$\frac{1}{81}x=\frac{9}{9}-\frac{2}{9}$$

Since \frac{9}{9} and \frac{2}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{81}x=\frac{9-2}{9}$$

Subtract 2 from 9 to get 7.

$$\frac{1}{81}x=\frac{7}{9}$$

Multiply both sides by 81, the reciprocal of \frac{1}{81}.

$$x=\frac{7}{9}\times 81$$

Express \frac{7}{9}\times 81 as a single fraction.

$$x=\frac{7\times 81}{9}$$

Multiply 7 and 81 to get 567.

$$x=\frac{567}{9}$$

Divide 567 by 9 to get 63.

$$x=63$$