Solve 16^3-5*16^3/24^3-2*160^2

$$\frac { 16 ^ { 3 } - 5 \cdot 16 ^ { 3 } } { 24 ^ { 3 } - 2 \cdot 160 ^ { 2 } }$$

Evaluate

$$\frac{32}{73}\approx 0.438356164$$

Solution Steps

Calculate 16 to the power of 3 and get 4096.

$$\frac{4096-5\times 16^{3}}{24^{3}-2\times 160^{2}}$$

Calculate 16 to the power of 3 and get 4096.

$$\frac{4096-5\times 4096}{24^{3}-2\times 160^{2}}$$

Multiply 5 and 4096 to get 20480.

$$\frac{4096-20480}{24^{3}-2\times 160^{2}}$$

Subtract 20480 from 4096 to get -16384.

$$\frac{-16384}{24^{3}-2\times 160^{2}}$$

Calculate 24 to the power of 3 and get 13824.

$$\frac{-16384}{13824-2\times 160^{2}}$$

Calculate 160 to the power of 2 and get 25600.

$$\frac{-16384}{13824-2\times 25600}$$

Multiply 2 and 25600 to get 51200.

$$\frac{-16384}{13824-51200}$$

Subtract 51200 from 13824 to get -37376.

$$\frac{-16384}{-37376}$$

Reduce the fraction \frac{-16384}{-37376} to lowest terms by extracting and canceling out -512.

$$\frac{32}{73}$$

Factor

$$\frac{2 ^ {5}}{73} = 0.4383561643835616$$