Solve 16^2-8^2/-3(8-3^2)

$$\frac { 16 ^ { 2 } - 8 ^ { 2 } } { - 3 ( 8 - 3 ^ { 2 } ) }$$

Evaluate

$$64$$

Solution Steps

Calculate 16 to the power of 2 and get 256.

$$\frac{256-8^{2}}{-3\left(8-3^{2}\right)}$$

Calculate 8 to the power of 2 and get 64.

$$\frac{256-64}{-3\left(8-3^{2}\right)}$$

Subtract 64 from 256 to get 192.

$$\frac{192}{-3\left(8-3^{2}\right)}$$

Calculate 3 to the power of 2 and get 9.

$$\frac{192}{-3\left(8-9\right)}$$

Subtract 9 from 8 to get -1.

$$\frac{192}{-3\left(-1\right)}$$

Multiply -3 and -1 to get 3.

$$\frac{192}{3}$$

Divide 192 by 3 to get 64.

$$64$$

Factor

$$2^{6}$$