Solve for k
k=3
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\frac{30}{7}k=\frac{90}{7}
Reduce the fraction \frac{150}{35} to lowest terms by extracting and canceling out 5.
k=\frac{90}{7}\times \frac{7}{30}
Multiply both sides by \frac{7}{30}, the reciprocal of \frac{30}{7}.
k=\frac{90\times 7}{7\times 30}
Multiply \frac{90}{7} times \frac{7}{30} by multiplying numerator times numerator and denominator times denominator.
k=\frac{90}{30}
Cancel out 7 in both numerator and denominator.
k=3
Divide 90 by 30 to get 3.
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