Solve 15x-3/5+4<x

$$\frac { 15 x - 3 } { 5 } + 4 < x$$

Solve for x

$$x<-\frac{17}{10}$$

Solution Steps

Divide each term of 15x-3 by 5 to get 3x-\frac{3}{5}.

$$3x-\frac{3}{5}+4<x$$

Convert 4 to fraction \frac{20}{5}.

$$3x-\frac{3}{5}+\frac{20}{5}<x$$

Since -\frac{3}{5} and \frac{20}{5} have the same denominator, add them by adding their numerators.

$$3x+\frac{-3+20}{5}<x$$

Add -3 and 20 to get 17.

$$3x+\frac{17}{5}<x$$

Subtract x from both sides.

$$3x+\frac{17}{5}-x<0$$

Combine 3x and -x to get 2x.

$$2x+\frac{17}{5}<0$$

Subtract \frac{17}{5} from both sides. Anything subtracted from zero gives its negation.

$$2x<-\frac{17}{5}$$

Divide both sides by 2. Since 2 is positive, the inequality direction remains the same.

$$x<\frac{-\frac{17}{5}}{2}$$

Express \frac{-\frac{17}{5}}{2} as a single fraction.

$$x<\frac{-17}{5\times 2}$$

Multiply 5 and 2 to get 10.

$$x<\frac{-17}{10}$$

Fraction \frac{-17}{10} can be rewritten as -\frac{17}{10} by extracting the negative sign.

$$x<-\frac{17}{10}$$