Solve 141/6(33+1.955+1.33*1.955)

$$\frac { 141 } { 6 } ( 33 + 1.955 + 1.33 \times 1.955 )$$

Evaluate

$$882.546025$$

Solution Steps

Reduce the fraction \frac{141}{6} to lowest terms by extracting and canceling out 3.

$$\frac{47}{2}\left(33+1.955+1.33\times 1.955\right)$$

Add 33 and 1.955 to get 34.955.

$$\frac{47}{2}\left(34.955+1.33\times 1.955\right)$$

Multiply 1.33 and 1.955 to get 2.60015.

$$\frac{47}{2}\left(34.955+2.60015\right)$$

Add 34.955 and 2.60015 to get 37.55515.

$$\frac{47}{2}\times 37.55515$$

Convert decimal number 37.55515 to fraction \frac{3755515}{100000}. Reduce the fraction \frac{3755515}{100000} to lowest terms by extracting and canceling out 5.

$$\frac{47}{2}\times \frac{751103}{20000}$$

Multiply \frac{47}{2} times \frac{751103}{20000} by multiplying numerator times numerator and denominator times denominator.

$$\frac{47\times 751103}{2\times 20000}$$

Do the multiplications in the fraction \frac{47\times 751103}{2\times 20000}.

$$\frac{35301841}{40000}$$

Factor

$$\frac{47 \cdot 751103}{2 ^ {6} \cdot 5 ^ {4}} = 882\frac{21841}{40000} = 882.546025$$