Solve 14x^6/y^3*2y/7x^3

$$\frac { 14 x ^ { 6 } } { y ^ { 3 } } \times \frac { 2 y } { 7 x ^ { 3 } }$$

Evaluate

$$\frac{4x^{3}}{y^{2}}$$

Solution Steps

Multiply \frac{14x^{6}}{y^{3}} times \frac{2y}{7x^{3}} by multiplying numerator times numerator and denominator times denominator.

$$\frac{14x^{6}\times 2y}{y^{3}\times 7x^{3}}$$

Cancel out 7yx^{3} in both numerator and denominator.

$$\frac{2\times 2x^{3}}{y^{2}}$$

Multiply 2 and 2 to get 4.

$$\frac{4x^{3}}{y^{2}}$$

Differentiate w.r.t. x

$$12\times \left(\frac{x}{y}\right)^{2}$$