Solve 14/8+14/6+11/12

$$\frac { 14 } { 8 } + \frac { 14 } { 6 } + \frac { 11 } { 12 }$$

Evaluate

$$5$$

Solution Steps

Reduce the fraction \frac{14}{8} to lowest terms by extracting and canceling out 2.

$$\frac{7}{4}+\frac{14}{6}+\frac{11}{12}$$

Reduce the fraction \frac{14}{6} to lowest terms by extracting and canceling out 2.

$$\frac{7}{4}+\frac{7}{3}+\frac{11}{12}$$

Least common multiple of 4 and 3 is 12. Convert \frac{7}{4} and \frac{7}{3} to fractions with denominator 12.

$$\frac{21}{12}+\frac{28}{12}+\frac{11}{12}$$

Since \frac{21}{12} and \frac{28}{12} have the same denominator, add them by adding their numerators.

$$\frac{21+28}{12}+\frac{11}{12}$$

Add 21 and 28 to get 49.

$$\frac{49}{12}+\frac{11}{12}$$

Since \frac{49}{12} and \frac{11}{12} have the same denominator, add them by adding their numerators.

$$\frac{49+11}{12}$$

Add 49 and 11 to get 60.

$$\frac{60}{12}$$

Divide 60 by 12 to get 5.

$$5$$

Factor

$$5$$