Solve 14/15-5/9=42/45-20/36=frac{22}{36}

$$\frac { 14 } { 15 } - \frac { 5 } { 9 } = \frac { 42 } { 45 } - \frac { 20 } { 36 } = \frac { 22 } { 36 }$$

Verify

Solution Steps

Least common multiple of 15 and 9 is 45. Convert \frac{14}{15} and \frac{5}{9} to fractions with denominator 45.

$$\frac{42}{45}-\frac{25}{45}=\frac{42}{45}-\frac{20}{36}\text{ and }\frac{42}{45}-\frac{20}{36}=\frac{22}{36}$$

Since \frac{42}{45} and \frac{25}{45} have the same denominator, subtract them by subtracting their numerators.

$$\frac{42-25}{45}=\frac{42}{45}-\frac{20}{36}\text{ and }\frac{42}{45}-\frac{20}{36}=\frac{22}{36}$$

Subtract 25 from 42 to get 17.

$$\frac{17}{45}=\frac{42}{45}-\frac{20}{36}\text{ and }\frac{42}{45}-\frac{20}{36}=\frac{22}{36}$$

Reduce the fraction \frac{42}{45} to lowest terms by extracting and canceling out 3.

$$\frac{17}{45}=\frac{14}{15}-\frac{20}{36}\text{ and }\frac{42}{45}-\frac{20}{36}=\frac{22}{36}$$

Reduce the fraction \frac{20}{36} to lowest terms by extracting and canceling out 4.

$$\frac{17}{45}=\frac{14}{15}-\frac{5}{9}\text{ and }\frac{42}{45}-\frac{20}{36}=\frac{22}{36}$$

Least common multiple of 15 and 9 is 45. Convert \frac{14}{15} and \frac{5}{9} to fractions with denominator 45.

$$\frac{17}{45}=\frac{42}{45}-\frac{25}{45}\text{ and }\frac{42}{45}-\frac{20}{36}=\frac{22}{36}$$

Since \frac{42}{45} and \frac{25}{45} have the same denominator, subtract them by subtracting their numerators.

$$\frac{17}{45}=\frac{42-25}{45}\text{ and }\frac{42}{45}-\frac{20}{36}=\frac{22}{36}$$

Subtract 25 from 42 to get 17.

$$\frac{17}{45}=\frac{17}{45}\text{ and }\frac{42}{45}-\frac{20}{36}=\frac{22}{36}$$

Compare \frac{17}{45} and \frac{17}{45}.

$$\text{true}\text{ and }\frac{42}{45}-\frac{20}{36}=\frac{22}{36}$$

Reduce the fraction \frac{42}{45} to lowest terms by extracting and canceling out 3.

$$\text{true}\text{ and }\frac{14}{15}-\frac{20}{36}=\frac{22}{36}$$

Reduce the fraction \frac{20}{36} to lowest terms by extracting and canceling out 4.

$$\text{true}\text{ and }\frac{14}{15}-\frac{5}{9}=\frac{22}{36}$$

Least common multiple of 15 and 9 is 45. Convert \frac{14}{15} and \frac{5}{9} to fractions with denominator 45.

$$\text{true}\text{ and }\frac{42}{45}-\frac{25}{45}=\frac{22}{36}$$

Since \frac{42}{45} and \frac{25}{45} have the same denominator, subtract them by subtracting their numerators.

$$\text{true}\text{ and }\frac{42-25}{45}=\frac{22}{36}$$

Subtract 25 from 42 to get 17.

$$\text{true}\text{ and }\frac{17}{45}=\frac{22}{36}$$

Reduce the fraction \frac{22}{36} to lowest terms by extracting and canceling out 2.

$$\text{true}\text{ and }\frac{17}{45}=\frac{11}{18}$$

Least common multiple of 45 and 18 is 90. Convert \frac{17}{45} and \frac{11}{18} to fractions with denominator 90.

$$\text{true}\text{ and }\frac{34}{90}=\frac{55}{90}$$

Compare \frac{34}{90} and \frac{55}{90}.

$$\text{true}\text{ and }\text{false}$$

The conjunction of \text{true} and \text{false} is \text{false}.

$$\text{false}$$