Solve 13y+1/3y+2-7y-3/3y+2

$$\frac { 13 y + 1 } { 3 y + 2 } - \frac { 7 y - 3 } { 3 y + 2 }$$

Evaluate

$$2$$

Short Solution Steps

Since \frac{13y+1}{3y+2} and \frac{7y-3}{3y+2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{13y+1-\left(7y-3\right)}{3y+2}$$

Do the multiplications in 13y+1-\left(7y-3\right).

$$\frac{13y+1-7y+3}{3y+2}$$

Combine like terms in 13y+1-7y+3.

$$\frac{6y+4}{3y+2}$$

Factor the expressions that are not already factored in \frac{6y+4}{3y+2}.

$$\frac{2\left(3y+2\right)}{3y+2}$$

Cancel out 3y+2 in both numerator and denominator.

$$2$$

Factor

$$2$$