Solve 13-15x/4geq1-3xZ2-x<7

$$\frac { 13 - 15 x } { 4 } \geq 1 - 3 x Z 2 - x < 7$$

Solve for x

$$\left\{\begin{matrix}x>-\frac{8}{5}\text{, }&Z_{2}=\frac{11}{12}\\x\in (-\frac{6}{3Z_{2}+1},-\frac{9}{12Z_{2}-11}]\text{, }&Z_{2}>-\frac{1}{3}\text{ and }Z_{2}<\frac{11}{12}\\x\leq -\frac{9}{12Z_{2}-11}\text{, }&Z_{2}<-\frac{1}{3}\\x>-\frac{6}{3Z_{2}+1}\text{, }&Z_{2}>\frac{11}{12}\text{ and }Z_{2}\leq \frac{5}{3}\\x\geq -\frac{9}{12Z_{2}-11}\text{, }&Z_{2}>\frac{5}{3}\\x\leq \frac{3}{5}\text{, }&Z_{2}=-\frac{1}{3}\end{matrix}\right.$$

Solve for Z_2

$$\left\{\begin{matrix}Z_{2}\in \mathrm{R}\text{, }&x=0\\Z_{2}<-\frac{1}{3}-\frac{2}{x}\text{, }&x\leq -1\\Z_{2}\leq \frac{11}{12}-\frac{3}{4x}\text{, }&x>-1\text{ and }x<0\\Z_{2}\geq \frac{11}{12}-\frac{3}{4x}\text{, }&x>0\end{matrix}\right.$$