Solve for t
t=-\frac{9}{10}=-0.9
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\frac{13}{20}+\frac{10}{20}-\frac{1}{4}=-t
Least common multiple of 20 and 2 is 20. Convert \frac{13}{20} and \frac{1}{2} to fractions with denominator 20.
\frac{13+10}{20}-\frac{1}{4}=-t
Since \frac{13}{20} and \frac{10}{20} have the same denominator, add them by adding their numerators.
\frac{23}{20}-\frac{1}{4}=-t
Add 13 and 10 to get 23.
\frac{23}{20}-\frac{5}{20}=-t
Least common multiple of 20 and 4 is 20. Convert \frac{23}{20} and \frac{1}{4} to fractions with denominator 20.
\frac{23-5}{20}=-t
Since \frac{23}{20} and \frac{5}{20} have the same denominator, subtract them by subtracting their numerators.
\frac{18}{20}=-t
Subtract 5 from 23 to get 18.
\frac{9}{10}=-t
Reduce the fraction \frac{18}{20} to lowest terms by extracting and canceling out 2.
-t=\frac{9}{10}
Swap sides so that all variable terms are on the left hand side.
t=-\frac{9}{10}
Multiply both sides by -1.
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