Solve for x
x=-8
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\frac{7}{3}x+\frac{5}{3}=-\frac{221}{2}\times \frac{2}{13}
Multiply both sides by \frac{2}{13}, the reciprocal of \frac{13}{2}.
\frac{7}{3}x+\frac{5}{3}=\frac{-221\times 2}{2\times 13}
Multiply -\frac{221}{2} times \frac{2}{13} by multiplying numerator times numerator and denominator times denominator.
\frac{7}{3}x+\frac{5}{3}=\frac{-221}{13}
Cancel out 2 in both numerator and denominator.
\frac{7}{3}x+\frac{5}{3}=-17
Divide -221 by 13 to get -17.
\frac{7}{3}x=-17-\frac{5}{3}
Subtract \frac{5}{3} from both sides.
\frac{7}{3}x=-\frac{51}{3}-\frac{5}{3}
Convert -17 to fraction -\frac{51}{3}.
\frac{7}{3}x=\frac{-51-5}{3}
Since -\frac{51}{3} and \frac{5}{3} have the same denominator, subtract them by subtracting their numerators.
\frac{7}{3}x=-\frac{56}{3}
Subtract 5 from -51 to get -56.
x=-\frac{56}{3}\times \frac{3}{7}
Multiply both sides by \frac{3}{7}, the reciprocal of \frac{7}{3}.
x=\frac{-56\times 3}{3\times 7}
Multiply -\frac{56}{3} times \frac{3}{7} by multiplying numerator times numerator and denominator times denominator.
x=\frac{-56}{7}
Cancel out 3 in both numerator and denominator.
x=-8
Divide -56 by 7 to get -8.
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