Solve 13/18-8/9+1/6

$$\frac { 13 } { 18 } - \frac { 8 } { 9 } + \frac { 1 } { 6 }$$

Evaluate

$$0$$

Solution Steps

Least common multiple of 18 and 9 is 18. Convert \frac{13}{18} and \frac{8}{9} to fractions with denominator 18.

$$\frac{13}{18}-\frac{16}{18}+\frac{1}{6}$$

Since \frac{13}{18} and \frac{16}{18} have the same denominator, subtract them by subtracting their numerators.

$$\frac{13-16}{18}+\frac{1}{6}$$

Subtract 16 from 13 to get -3.

$$\frac{-3}{18}+\frac{1}{6}$$

Reduce the fraction \frac{-3}{18} to lowest terms by extracting and canceling out 3.

$$-\frac{1}{6}+\frac{1}{6}$$

Add -\frac{1}{6} and \frac{1}{6} to get 0.

$$0$$

Factor

$$0$$