Solve 13+1/2geq9x-5

$$\frac { 13 + 1 } { 2 } \geq 9 x - 5$$

Solve for x

$$x\leq \frac{4}{3}$$

Solution Steps

Multiply both sides of the equation by 2. Since 2 is positive, the inequality direction remains the same.

$$13+1\geq 18x-10$$

Add 13 and 1 to get 14.

$$14\geq 18x-10$$

Swap sides so that all variable terms are on the left hand side. This changes the sign direction.

$$18x-10\leq 14$$

Add 10 to both sides.

$$18x\leq 14+10$$

Add 14 and 10 to get 24.

$$18x\leq 24$$

Divide both sides by 18. Since 18 is positive, the inequality direction remains the same.

$$x\leq \frac{24}{18}$$

Reduce the fraction \frac{24}{18} to lowest terms by extracting and canceling out 6.

$$x\leq \frac{4}{3}$$