Solve 120-10x/0.04=54+10x/0.06

$$\frac { 120 - 10 x } { 0.04 } = \frac { 54 + 10 x } { 0.06 }$$

Solve for x

$$x=5.04$$

Steps for Solving Linear Equation

Divide each term of 120-10x by 0.04 to get \frac{120}{0.04}+\frac{-10x}{0.04}.

$$\frac{120}{0.04}+\frac{-10x}{0.04}=\frac{54+10x}{0.06}$$

Expand \frac{120}{0.04} by multiplying both numerator and the denominator by 100.

$$\frac{12000}{4}+\frac{-10x}{0.04}=\frac{54+10x}{0.06}$$

Divide 12000 by 4 to get 3000.

$$3000+\frac{-10x}{0.04}=\frac{54+10x}{0.06}$$

Divide -10x by 0.04 to get -250x.

$$3000-250x=\frac{54+10x}{0.06}$$

Divide each term of 54+10x by 0.06 to get \frac{54}{0.06}+\frac{10x}{0.06}.

$$3000-250x=\frac{54}{0.06}+\frac{10x}{0.06}$$

Expand \frac{54}{0.06} by multiplying both numerator and the denominator by 100.

$$3000-250x=\frac{5400}{6}+\frac{10x}{0.06}$$

Divide 5400 by 6 to get 900.

$$3000-250x=900+\frac{10x}{0.06}$$

Divide 10x by 0.06 to get \frac{500}{3}x.

$$3000-250x=900+\frac{500}{3}x$$

Subtract \frac{500}{3}x from both sides.

$$3000-250x-\frac{500}{3}x=900$$

Combine -250x and -\frac{500}{3}x to get -\frac{1250}{3}x.

$$3000-\frac{1250}{3}x=900$$

Subtract 3000 from both sides.

$$-\frac{1250}{3}x=900-3000$$

Subtract 3000 from 900 to get -2100.

$$-\frac{1250}{3}x=-2100$$

Divide both sides by -\frac{1250}{3}.

$$x=\frac{-2100}{-\frac{1250}{3}}$$