Solve 120/1030+120/50+50/120

$$\frac { 120 } { 1030 } + \frac { 120 } { 50 } + \frac { 50 } { 120 }$$

Evaluate

$$\frac{18127}{6180}\approx 2.933171521$$

Solution Steps

Reduce the fraction \frac{120}{1030} to lowest terms by extracting and canceling out 10.

$$\frac{12}{103}+\frac{120}{50}+\frac{50}{120}$$

Reduce the fraction \frac{120}{50} to lowest terms by extracting and canceling out 10.

$$\frac{12}{103}+\frac{12}{5}+\frac{50}{120}$$

Least common multiple of 103 and 5 is 515. Convert \frac{12}{103} and \frac{12}{5} to fractions with denominator 515.

$$\frac{60}{515}+\frac{1236}{515}+\frac{50}{120}$$

Since \frac{60}{515} and \frac{1236}{515} have the same denominator, add them by adding their numerators.

$$\frac{60+1236}{515}+\frac{50}{120}$$

Add 60 and 1236 to get 1296.

$$\frac{1296}{515}+\frac{50}{120}$$

Reduce the fraction \frac{50}{120} to lowest terms by extracting and canceling out 10.

$$\frac{1296}{515}+\frac{5}{12}$$

Least common multiple of 515 and 12 is 6180. Convert \frac{1296}{515} and \frac{5}{12} to fractions with denominator 6180.

$$\frac{15552}{6180}+\frac{2575}{6180}$$

Since \frac{15552}{6180} and \frac{2575}{6180} have the same denominator, add them by adding their numerators.

$$\frac{15552+2575}{6180}$$

Add 15552 and 2575 to get 18127.

$$\frac{18127}{6180}$$

Factor

$$\frac{18127}{2 ^ {2} \cdot 3 \cdot 5 \cdot 103} = 2\frac{5767}{6180} = 2.933171521035599$$