Solve 120*10^6/[0.5*0.448*0.851*300*(430)^2]

$$\frac { 120 \times 10 ^ { 6 } } { [ 0.5 \times 0.448 \times 0.851 \times 300 \times ( 430 ) ^ { 2 } ] }$$

Evaluate

$$\frac{125000000}{11014493}\approx 11.348683957$$

Solution Steps

Cancel out 60 in both numerator and denominator.

$$\frac{2\times 10^{6}}{0.448\times 0.5\times 0.851\times 5\times 430^{2}}$$

Calculate 10 to the power of 6 and get 1000000.

$$\frac{2\times 1000000}{0.448\times 0.5\times 0.851\times 5\times 430^{2}}$$

Multiply 2 and 1000000 to get 2000000.

$$\frac{2000000}{0.448\times 0.5\times 0.851\times 5\times 430^{2}}$$

Multiply 0.448 and 0.5 to get 0.224.

$$\frac{2000000}{0.224\times 0.851\times 5\times 430^{2}}$$

Multiply 0.224 and 0.851 to get 0.190624.

$$\frac{2000000}{0.190624\times 5\times 430^{2}}$$

Multiply 0.190624 and 5 to get 0.95312.

$$\frac{2000000}{0.95312\times 430^{2}}$$

Calculate 430 to the power of 2 and get 184900.

$$\frac{2000000}{0.95312\times 184900}$$

Multiply 0.95312 and 184900 to get 176231.888.

$$\frac{2000000}{176231.888}$$

Expand \frac{2000000}{176231.888} by multiplying both numerator and the denominator by 1000.

$$\frac{2000000000}{176231888}$$

Reduce the fraction \frac{2000000000}{176231888} to lowest terms by extracting and canceling out 16.

$$\frac{125000000}{11014493}$$

Factor

$$\frac{2 ^ {6} \cdot 5 ^ {9}}{7 \cdot 23 \cdot 37 \cdot 43 ^ {2}} = 11\frac{3840577}{11014493} = 11.348683956674174$$