Solve 12x/x^2-9-4/x+3=12/x^2-9

$$\frac { 12 x } { x ^ { 2 } - 9 } - \frac { 4 } { x + 3 } = \frac { 12 } { x ^ { 2 } - 9 }$$

Solve for x

$$x=0$$

Steps for Solving Linear Equation

Variable x cannot be equal to any of the values -3,3 since division by zero is not defined. Multiply both sides of the equation by \left(x-3\right)\left(x+3\right), the least common multiple of x^{2}-9,x+3.

$$12x-\left(x-3\right)\times 4=12$$

Use the distributive property to multiply x-3 by 4.

$$12x-\left(4x-12\right)=12$$

To find the opposite of 4x-12, find the opposite of each term.

$$12x-4x+12=12$$

Combine 12x and -4x to get 8x.

$$8x+12=12$$

Subtract 12 from both sides.

$$8x=12-12$$

Subtract 12 from 12 to get 0.

$$8x=0$$

Product of two numbers is equal to 0 if at least one of them is 0. Since 8 is not equal to 0, x must be equal to 0.

$$x=0$$