Solve 12x+48/6-frac{96{x^2}}

$$\frac { 12 x + 48 } { 6 - \frac { 96 } { x ^ { 2 } } }$$

Evaluate

$$\frac{2x^{2}}{x-4}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 6 times \frac{x^{2}}{x^{2}}.

$$\frac{12x+48}{\frac{6x^{2}}{x^{2}}-\frac{96}{x^{2}}}$$

Since \frac{6x^{2}}{x^{2}} and \frac{96}{x^{2}} have the same denominator, subtract them by subtracting their numerators.

$$\frac{12x+48}{\frac{6x^{2}-96}{x^{2}}}$$

Divide 12x+48 by \frac{6x^{2}-96}{x^{2}} by multiplying 12x+48 by the reciprocal of \frac{6x^{2}-96}{x^{2}}.

$$\frac{\left(12x+48\right)x^{2}}{6x^{2}-96}$$

Factor the expressions that are not already factored.

$$\frac{12\left(x+4\right)x^{2}}{6\left(x-4\right)\left(x+4\right)}$$

Cancel out 6\left(x+4\right) in both numerator and denominator.

$$\frac{2x^{2}}{x-4}$$

Expand

$$\frac{2x^{2}}{x-4}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 6 times \frac{x^{2}}{x^{2}}.

$$\frac{12x+48}{\frac{6x^{2}}{x^{2}}-\frac{96}{x^{2}}}$$

Since \frac{6x^{2}}{x^{2}} and \frac{96}{x^{2}} have the same denominator, subtract them by subtracting their numerators.

$$\frac{12x+48}{\frac{6x^{2}-96}{x^{2}}}$$

Divide 12x+48 by \frac{6x^{2}-96}{x^{2}} by multiplying 12x+48 by the reciprocal of \frac{6x^{2}-96}{x^{2}}.

$$\frac{\left(12x+48\right)x^{2}}{6x^{2}-96}$$

Factor the expressions that are not already factored.

$$\frac{12\left(x+4\right)x^{2}}{6\left(x-4\right)\left(x+4\right)}$$

Cancel out 6\left(x+4\right) in both numerator and denominator.

$$\frac{2x^{2}}{x-4}$$