Solve 12x+48/3-frac{48{x^2}}

$$\frac { 12 x + 48 } { 3 - \frac { 48 } { x ^ { 2 } } }$$

Evaluate

$$\frac{4x^{2}}{x-4}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 3 times \frac{x^{2}}{x^{2}}.

$$\frac{12x+48}{\frac{3x^{2}}{x^{2}}-\frac{48}{x^{2}}}$$

Since \frac{3x^{2}}{x^{2}} and \frac{48}{x^{2}} have the same denominator, subtract them by subtracting their numerators.

$$\frac{12x+48}{\frac{3x^{2}-48}{x^{2}}}$$

Divide 12x+48 by \frac{3x^{2}-48}{x^{2}} by multiplying 12x+48 by the reciprocal of \frac{3x^{2}-48}{x^{2}}.

$$\frac{\left(12x+48\right)x^{2}}{3x^{2}-48}$$

Factor the expressions that are not already factored.

$$\frac{12\left(x+4\right)x^{2}}{3\left(x-4\right)\left(x+4\right)}$$

Cancel out 3\left(x+4\right) in both numerator and denominator.

$$\frac{4x^{2}}{x-4}$$

Expand

$$\frac{4x^{2}}{x-4}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 3 times \frac{x^{2}}{x^{2}}.

$$\frac{12x+48}{\frac{3x^{2}}{x^{2}}-\frac{48}{x^{2}}}$$

Since \frac{3x^{2}}{x^{2}} and \frac{48}{x^{2}} have the same denominator, subtract them by subtracting their numerators.

$$\frac{12x+48}{\frac{3x^{2}-48}{x^{2}}}$$

Divide 12x+48 by \frac{3x^{2}-48}{x^{2}} by multiplying 12x+48 by the reciprocal of \frac{3x^{2}-48}{x^{2}}.

$$\frac{\left(12x+48\right)x^{2}}{3x^{2}-48}$$

Factor the expressions that are not already factored.

$$\frac{12\left(x+4\right)x^{2}}{3\left(x-4\right)\left(x+4\right)}$$

Cancel out 3\left(x+4\right) in both numerator and denominator.

$$\frac{4x^{2}}{x-4}$$