Solve 12(-02+1)(-02+2)(-02+3)(04)/24

$$\frac { 12 ( - 02 + 1 ) ( - 02 + 2 ) ( - 02 + 3 ) ( 04 ) } { 24 }$$

Evaluate

$$0$$

Solution Steps

Multiply 0 and 2 to get 0.

$$\frac{12\left(0+1\right)\left(0\times 2+2\right)\left(0\times 2+3\right)\times 0\times 4}{24}$$

Add 0 and 1 to get 1.

$$\frac{12\times 1\left(0\times 2+2\right)\left(0\times 2+3\right)\times 0\times 4}{24}$$

Multiply 12 and 1 to get 12.

$$\frac{12\left(0\times 2+2\right)\left(0\times 2+3\right)\times 0\times 4}{24}$$

Multiply 0 and 2 to get 0.

$$\frac{12\left(0+2\right)\left(0\times 2+3\right)\times 0\times 4}{24}$$

Add 0 and 2 to get 2.

$$\frac{12\times 2\left(0\times 2+3\right)\times 0\times 4}{24}$$

Multiply 12 and 2 to get 24.

$$\frac{24\left(0\times 2+3\right)\times 0\times 4}{24}$$

Multiply 0 and 2 to get 0.

$$\frac{24\left(0+3\right)\times 0\times 4}{24}$$

Add 0 and 3 to get 3.

$$\frac{24\times 3\times 0\times 4}{24}$$

Multiply 24 and 3 to get 72.

$$\frac{72\times 0\times 4}{24}$$

Multiply 72 and 0 to get 0.

$$\frac{0\times 4}{24}$$

Multiply 0 and 4 to get 0.

$$\frac{0}{24}$$

Zero divided by any non-zero number gives zero.

$$0$$

Factor

$$0$$