Solve 12/4-sqrt{3}

$$\frac { 12 } { 4 - \sqrt { 3 } }$$

Evaluate

$$\frac{12\left(\sqrt{3}+4\right)}{13}\approx 5.291123822$$

Solution Steps

Rationalize the denominator of \frac{12}{4-\sqrt{3}} by multiplying numerator and denominator by 4+\sqrt{3}.

$$\frac{12\left(4+\sqrt{3}\right)}{\left(4-\sqrt{3}\right)\left(4+\sqrt{3}\right)}$$

Consider \left(4-\sqrt{3}\right)\left(4+\sqrt{3}\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$\frac{12\left(4+\sqrt{3}\right)}{4^{2}-\left(\sqrt{3}\right)^{2}}$$

Square 4. Square \sqrt{3}.

$$\frac{12\left(4+\sqrt{3}\right)}{16-3}$$

Subtract 3 from 16 to get 13.

$$\frac{12\left(4+\sqrt{3}\right)}{13}$$

Use the distributive property to multiply 12 by 4+\sqrt{3}.

$$\frac{48+12\sqrt{3}}{13}$$