Solve 12^2+2*12*7+7^2/(26)^2-(12)^2

$$\frac { 12 ^ { 2 } + 2 \cdot 12 \cdot 7 + 7 ^ { 2 } } { ( 26 ) ^ { 2 } - ( 12 ) ^ { 2 } }$$

Evaluate

$$\frac{19}{28}\approx 0.678571429$$

Solution Steps

Calculate 12 to the power of 2 and get 144.

$$\frac{144+2\times 12\times 7+7^{2}}{26^{2}-12^{2}}$$

Multiply 2 and 12 to get 24.

$$\frac{144+24\times 7+7^{2}}{26^{2}-12^{2}}$$

Multiply 24 and 7 to get 168.

$$\frac{144+168+7^{2}}{26^{2}-12^{2}}$$

Add 144 and 168 to get 312.

$$\frac{312+7^{2}}{26^{2}-12^{2}}$$

Calculate 7 to the power of 2 and get 49.

$$\frac{312+49}{26^{2}-12^{2}}$$

Add 312 and 49 to get 361.

$$\frac{361}{26^{2}-12^{2}}$$

Calculate 26 to the power of 2 and get 676.

$$\frac{361}{676-12^{2}}$$

Calculate 12 to the power of 2 and get 144.

$$\frac{361}{676-144}$$

Subtract 144 from 676 to get 532.

$$\frac{361}{532}$$

Reduce the fraction \frac{361}{532} to lowest terms by extracting and canceling out 19.

$$\frac{19}{28}$$

Factor

$$\frac{19}{2 ^ {2} \cdot 7} = 0.6785714285714286$$